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3.4=-0.8x^2-0.06x+3.4
We move all terms to the left:
3.4-(-0.8x^2-0.06x+3.4)=0
We get rid of parentheses
0.8x^2+0.06x-3.4+3.4=0
We add all the numbers together, and all the variables
0.8x^2+0.06x=0
a = 0.8; b = 0.06; c = 0;
Δ = b2-4ac
Δ = 0.062-4·0.8·0
Δ = 0.0036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.0036}}{2*0.8}=\frac{-0.06-\sqrt{0.0036}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.0036}}{2*0.8}=\frac{-0.06+\sqrt{0.0036}}{1.6} $
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